Math activity it is possible to find exercises of simple and complex sums, to complete the missing portion, of taking the real proof. These addition activities are designed for fourth- or fifth-year students.
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SCHOOL: DATE:
PROF: CLASS:
NAME:
THE SUM OF TWO NATURAL NUMBERS RESULTS IN A NATURAL NUMBER.
EG: 5 + 3 = 8
WHEN WE HAVE A SUM INVOLVING MORE THAN TWO NUMBERS, THE ASSOCIATION DOES NOT MATTER AND THE ORDER IN WHICH WE SUMMED IT DOES NOT CHANGE THE RESULT.
EG: 5 + 10 + 3 = OR 5 + 10 + 3 =
15 + 3 = 18 5 + 13 = 18
TO VERIFY IF THE RESULTS OF THE ADDITIONS, WE TAKE THE ACTUAL PROOF, ARE CORRECT, JUST TAKE THE RESULT AND SUBTRACT A PORTION ABOVE, THIS OPERATION MUST RESULT IN THE VALUE OF THE OTHER PORTION.
EG: 13 + 10 = 23
ACTUAL TEST: 23 - 10 = 13 OR 23 - 13 = 10
1) MAKE THE SUM BELOW:
A) 375
+249
B) 5720
+3096
1585
C) 461
+ 758
D) 3829
+ 6454
656
E) 836
+ 594
F) 32769
+ 1630
210
G) 521
+ 176
99
H) 7425
+ 5097
210
2) COMPLETE THE ADDITIONS BELOW WITH THE MISSING NUMBERS:
A) __ 7 __ __ __
+ 2 __ 3 6 5
7 7 7 7 7
B) 4 __ 5 __
+ 2 1 __ 2
__ 6 7 7
C) 8 7 3 9 6
+ _ _ 8 _ 5
8 _ 2 5 1
D) __ 3 __ 4
+ 1 __ 0 __
5 7 9 6
3) RESOLVE THE ADDITIONS BELOW:
A) 23 + 14 + 9 =
B) 18 + 7 + 9 =
C) 16 + 8 + 10 =
D) 35 + 12 + 26 =
E) 24 + 6 + 4 =
F) 3 + 15 + 5 =
G) 349 + 28 =
H) 731 + 189 =
I) 250 + 85 + 46 =
J) 448 + 302 + 95 =
K) 210 + 25 + 180 =
L) 825 + 730 =
4) RESOLVE THE ACCOUNTS BELOW BY STARTING WITH THE ACCOUNTS THAT ARE IN PARENTHESES:
A) (20 + 9) + 6 =
B) 40 + (10 + 60) =
C) (50 + 20) +11 =
D) 15 + (8 + 5) =
E) 18 + (12 + 12) =
F) 10 + (9 + 7) =
G) (9 + 9) + 17 =
H) (6 + 8) + 30 =
I) 25 + (60 + 40) =
J) (34 + 16) + 5 =
5) RESOLVE THE ACCOUNTS BELOW AND TAKE THE ACTUAL TEST, TO CONSULT THE RESULTS:
A) 6,498 + 3245 =
B) 2,035 + 6,821 =
C) 3,725 + 752 =
D) 26,853 + 45,826 =
E) 1,550 + 680 =
F) 8,325 + 5,589 =
G) 918 + 3,734 =
H) 26,890 + 14,738 =
For ACCESS
At answers are in the link above the header.
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